1326+3/20c=c

Solution for 1326+3/20c=c equation:

1326+3/20c=c

We move all terms to the left:

1326+3/20c-(c)=0


Domain of the equation: 20c!=0

c!=0/20

c!=0

c∈R


We add all the numbers together, and all the variables

-1c+3/20c+1326=0

We multiply all the terms by the denominator


-1c*20c+1326*20c+3=0

Wy multiply elements

-20c^2+26520c+3=0

a = -20; b = 26520; c = +3;
Δ = b2-4ac
Δ = 265202-4·(-20)·3
Δ = 703310640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{703310640}=\sqrt{16*43956915}=\sqrt{16}*\sqrt{43956915}=4\sqrt{43956915}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26520)-4\sqrt{43956915}}{2*-20}=\frac{-26520-4\sqrt{43956915}}{-40}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26520)+4\sqrt{43956915}}{2*-20}=\frac{-26520+4\sqrt{43956915}}{-40}
$