132=(1+5x)x

Solution for 132=(1+5x)x equation:

132=(1+5x)x

We move all terms to the left:

132-((1+5x)x)=0

We add all the numbers together, and all the variables

-((5x+1)x)+132=0


We calculate terms in parentheses: -((5x+1)x), so:

(5x+1)x

We multiply parentheses

5x^2+x

Back to the equation:

-(5x^2+x)


We get rid of parentheses

-5x^2-x+132=0

We add all the numbers together, and all the variables

-5x^2-1x+132=0

a = -5; b = -1; c = +132;
Δ = b2-4ac
Δ = -12-4·(-5)·132
Δ = 2641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{2641}}{2*-5}=\frac{1-\sqrt{2641}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{2641}}{2*-5}=\frac{1+\sqrt{2641}}{-10}
$