132=(4z+1)+(5z+2)

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Solution for 132=(4z+1)+(5z+2) equation:


Simplifying
132 = (4z + 1) + (5z + 2)

Reorder the terms:
132 = (1 + 4z) + (5z + 2)

Remove parenthesis around (1 + 4z)
132 = 1 + 4z + (5z + 2)

Reorder the terms:
132 = 1 + 4z + (2 + 5z)

Remove parenthesis around (2 + 5z)
132 = 1 + 4z + 2 + 5z

Reorder the terms:
132 = 1 + 2 + 4z + 5z

Combine like terms: 1 + 2 = 3
132 = 3 + 4z + 5z

Combine like terms: 4z + 5z = 9z
132 = 3 + 9z

Solving
132 = 3 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
132 + -9z = 3 + 9z + -9z

Combine like terms: 9z + -9z = 0
132 + -9z = 3 + 0
132 + -9z = 3

Add '-132' to each side of the equation.
132 + -132 + -9z = 3 + -132

Combine like terms: 132 + -132 = 0
0 + -9z = 3 + -132
-9z = 3 + -132

Combine like terms: 3 + -132 = -129
-9z = -129

Divide each side by '-9'.
z = 14.33333333

Simplifying
z = 14.33333333

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