132=10(3x+1)+2

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Solution for 132=10(3x+1)+2 equation: 



132=10(3x+1)+2

We move all terms to the left:

132-(10(3x+1)+2)=0



We calculate terms in parentheses: -(10(3x+1)+2), so:

10(3x+1)+2

We multiply parentheses

30x+10+2

We add all the numbers together, and all the variables

30x+12

Back to the equation:

-(30x+12)



We get rid of parentheses

-30x-12+132=0

We add all the numbers together, and all the variables

-30x+120=0

We move all terms containing x to the left, all other terms to the right

-30x=-120

x=-120/-30

x=+4

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