132=4(1+4r)

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Solution for 132=4(1+4r) equation: 



132=4(1+4r)

We move all terms to the left:

132-(4(1+4r))=0

We add all the numbers together, and all the variables

-(4(4r+1))+132=0



We calculate terms in parentheses: -(4(4r+1)), so:

4(4r+1)

We multiply parentheses

16r+4

Back to the equation:

-(16r+4)



We get rid of parentheses

-16r-4+132=0

We add all the numbers together, and all the variables

-16r+128=0

We move all terms containing r to the left, all other terms to the right

-16r=-128

r=-128/-16

r=+8

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