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132=x(x-2)
We move all terms to the left:
132-(x(x-2))=0
We calculate terms in parentheses: -(x(x-2)), so:We get rid of parentheses
x(x-2)
We multiply parentheses
x^2-2x
Back to the equation:
-(x^2-2x)
-x^2+2x+132=0
We add all the numbers together, and all the variables
-1x^2+2x+132=0
a = -1; b = 2; c = +132;
Δ = b2-4ac
Δ = 22-4·(-1)·132
Δ = 532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{532}=\sqrt{4*133}=\sqrt{4}*\sqrt{133}=2\sqrt{133}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{133}}{2*-1}=\frac{-2-2\sqrt{133}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{133}}{2*-1}=\frac{-2+2\sqrt{133}}{-2} $
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