133=7(1+2v)

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Solution for 133=7(1+2v) equation: 



133=7(1+2v)

We move all terms to the left:

133-(7(1+2v))=0

We add all the numbers together, and all the variables

-(7(2v+1))+133=0



We calculate terms in parentheses: -(7(2v+1)), so:

7(2v+1)

We multiply parentheses

14v+7

Back to the equation:

-(14v+7)



We get rid of parentheses

-14v-7+133=0

We add all the numbers together, and all the variables

-14v+126=0

We move all terms containing v to the left, all other terms to the right

-14v=-126

v=-126/-14

v=+9

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