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134=x(x-5)
We move all terms to the left:
134-(x(x-5))=0
We calculate terms in parentheses: -(x(x-5)), so:We get rid of parentheses
x(x-5)
We multiply parentheses
x^2-5x
Back to the equation:
-(x^2-5x)
-x^2+5x+134=0
We add all the numbers together, and all the variables
-1x^2+5x+134=0
a = -1; b = 5; c = +134;
Δ = b2-4ac
Δ = 52-4·(-1)·134
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{561}}{2*-1}=\frac{-5-\sqrt{561}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{561}}{2*-1}=\frac{-5+\sqrt{561}}{-2} $
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