135=(13x/3)+(5x-5)

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Solution for 135=(13x/3)+(5x-5) equation: 



135=(13x/3)+(5x-5)

We move all terms to the left:

135-((13x/3)+(5x-5))=0



Domain of the equation: 3)+(5x-5))!=0

x∈R



We add all the numbers together, and all the variables

-((+13x/3)+(5x-5))+135=0

We multiply all the terms by the denominator


-((+13x+135*3)+(5x-5))=0



We calculate terms in parentheses: -((+13x+135*3)+(5x-5)), so:

(+13x+135*3)+(5x-5)

We add all the numbers together, and all the variables

(13x+405)+(5x-5)

We get rid of parentheses

13x+5x+405-5

We add all the numbers together, and all the variables

18x+400

Back to the equation:

-(18x+400)



We get rid of parentheses

-18x-400=0

We move all terms containing x to the left, all other terms to the right

-18x=400

x=400/-18

x=-22+2/9

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