135=(180(n-2))/(n)

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Solution for 135=(180(n-2))/(n) equation:



135=(180(n-2))/(n)
We move all terms to the left:
135-((180(n-2))/(n))=0
Domain of the equation: n)!=0
n!=0/1
n!=0
n∈R
We multiply all the terms by the denominator
-((180(n-2))+135*n)=0
We calculate terms in parentheses: -((180(n-2))+135*n), so:
(180(n-2))+135*n
We add all the numbers together, and all the variables
135n+(180(n-2))
We calculate terms in parentheses: +(180(n-2)), so:
180(n-2)
We multiply parentheses
180n-360
Back to the equation:
+(180n-360)
We get rid of parentheses
135n+180n-360
We add all the numbers together, and all the variables
315n-360
Back to the equation:
-(315n-360)
We get rid of parentheses
-315n+360=0
We move all terms containing n to the left, all other terms to the right
-315n=-360
n=-360/-315
n=1+1/7

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