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135=(2y+3)(2y-3
We move all terms to the left:
135-((2y+3)(2y-3)=0
We use the square of the difference formula
4y^2+9=0
a = 4; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·4·9
Δ = -144
Delta is less than zero, so there is no solution for the equation
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