136+12x=63x2

Solution for 136+12x=63x2 equation:

136+12x=63x^2

We move all terms to the left:

136+12x-(63x^2)=0

determiningTheFunctionDomain
-63x^2+12x+136=0

a = -63; b = 12; c = +136;
Δ = b2-4ac
Δ = 122-4·(-63)·136
Δ = 34416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{34416}=\sqrt{144*239}=\sqrt{144}*\sqrt{239}=12\sqrt{239}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{239}}{2*-63}=\frac{-12-12\sqrt{239}}{-126}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{239}}{2*-63}=\frac{-12+12\sqrt{239}}{-126}
$