136=(x+17)(x-12)

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Solution for 136=(x+17)(x-12) equation:



136=(x+17)(x-12)
We move all terms to the left:
136-((x+17)(x-12))=0
We multiply parentheses ..
-((+x^2-12x+17x-204))+136=0
We calculate terms in parentheses: -((+x^2-12x+17x-204)), so:
(+x^2-12x+17x-204)
We get rid of parentheses
x^2-12x+17x-204
We add all the numbers together, and all the variables
x^2+5x-204
Back to the equation:
-(x^2+5x-204)
We get rid of parentheses
-x^2-5x+204+136=0
We add all the numbers together, and all the variables
-1x^2-5x+340=0
a = -1; b = -5; c = +340;
Δ = b2-4ac
Δ = -52-4·(-1)·340
Δ = 1385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1385}}{2*-1}=\frac{5-\sqrt{1385}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1385}}{2*-1}=\frac{5+\sqrt{1385}}{-2} $

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