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136=24/3(2x-1)
We move all terms to the left:
136-(24/3(2x-1))=0
Domain of the equation: 3(2x-1))!=0We multiply all the terms by the denominator
x∈R
-(24+136*3(2x-1))=0
We calculate terms in parentheses: -(24+136*3(2x-1)), so:We add all the numbers together, and all the variables
24+136*3(2x-1)
determiningTheFunctionDomain 136*3(2x-1)+24
Wy multiply elements
408x(2+24
Back to the equation:
-(408x(2+24)
-(408x26=0
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