136=3z+2+3z+2+4z+3+4z+3

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Solution for 136=3z+2+3z+2+4z+3+4z+3 equation: 



136=3z+2+3z+2+4z+3+4z+3

We move all terms to the left:

136-(3z+2+3z+2+4z+3+4z+3)=0

We add all the numbers together, and all the variables

-(14z+10)+136=0

We get rid of parentheses

-14z-10+136=0

We add all the numbers together, and all the variables

-14z+126=0

We move all terms containing z to the left, all other terms to the right

-14z=-126

z=-126/-14

z=+9

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