139+3x+(5x-10)+(10x-9)+3x=540

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Solution for 139+3x+(5x-10)+(10x-9)+3x=540 equation: 



139+3x+(5x-10)+(10x-9)+3x=540

We move all terms to the left:

139+3x+(5x-10)+(10x-9)+3x-(540)=0

We add all the numbers together, and all the variables

6x+(5x-10)+(10x-9)-401=0

We get rid of parentheses

6x+5x+10x-10-9-401=0

We add all the numbers together, and all the variables

21x-420=0

We move all terms containing x to the left, all other terms to the right

21x=420

x=420/21

x=20

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