13=(-2x)*(-2x)-12x+13

Solution for 13=(-2x)*(-2x)-12x+13 equation:

13=(-2x)(-2x)-12x+13

We move all terms to the left:

13-((-2x)(-2x)-12x+13)=0

We multiply parentheses ..

-((+4x^2)-12x+13)+13=0


We calculate terms in parentheses: -((+4x^2)-12x+13), so:

(+4x^2)-12x+13

We get rid of parentheses

4x^2-12x+13

Back to the equation:

-(4x^2-12x+13)


We get rid of parentheses

-4x^2+12x-13+13=0

We add all the numbers together, and all the variables

-4x^2+12x=0

a = -4; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-4)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-4}=\frac{-24}{-8}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-4}=\frac{0}{-8}
=0
$