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13=(1/3x)-5
We move all terms to the left:
13-((1/3x)-5)=0
Domain of the equation: 3x)-5)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+1/3x)-5)+13=0
We multiply all the terms by the denominator
-((+1+13*3x)-5)=0
We calculate terms in parentheses: -((+1+13*3x)-5), so:We get rid of parentheses
(+1+13*3x)-5
We add all the numbers together, and all the variables
(13*3x+1)-5
We get rid of parentheses
13*3x+1-5
We add all the numbers together, and all the variables
13*3x-4
Wy multiply elements
39x-4
Back to the equation:
-(39x-4)
-39x+4=0
We move all terms containing x to the left, all other terms to the right
-39x=-4
x=-4/-39
x=4/39
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