13=(1/6)y+2y

Solution for 13=(1/6)y+2y equation:

13=(1/6)y+2y

We move all terms to the left:

13-((1/6)y+2y)=0


Domain of the equation: 6)y+2y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-((+1/6)y+2y)+13=0

We multiply all the terms by the denominator


-((+1+13*6)y+2y)=0


We calculate terms in parentheses: -((+1+13*6)y+2y), so:

(+1+13*6)y+2y

We add all the numbers together, and all the variables

79y+2y

We add all the numbers together, and all the variables

81y

Back to the equation:

-(81y)


y=0/-81

y=0

Równanie nie ma rozwiązania