13=(3+5x)(-2-2x)+5

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Solution for 13=(3+5x)(-2-2x)+5 equation: 



13=(3+5x)(-2-2x)+5

We move all terms to the left:

13-((3+5x)(-2-2x)+5)=0

We add all the numbers together, and all the variables

-((5x+3)(-2x-2)+5)+13=0

We multiply parentheses ..

-((-10x^2-10x-6x-6)+5)+13=0



We calculate terms in parentheses: -((-10x^2-10x-6x-6)+5), so:

(-10x^2-10x-6x-6)+5

We get rid of parentheses

-10x^2-10x-6x-6+5

We add all the numbers together, and all the variables

-10x^2-16x-1

Back to the equation:

-(-10x^2-16x-1)



We get rid of parentheses

10x^2+16x+1+13=0

We add all the numbers together, and all the variables

10x^2+16x+14=0

a = 10; b = 16; c = +14;
Δ = b2-4ac
Δ = 162-4·10·14
Δ = -304
Delta is less than zero, so there is no solution for the equation

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