13=(x-3)+x/1+6

Solution for 13=(x-3)+x/1+6 equation:

13=(x-3)+x/1+6

We move all terms to the left:

13-((x-3)+x/1+6)=0

We multiply all the terms by the denominator


-((x-3)+x+13*1+6)=0


We calculate terms in parentheses: -((x-3)+x+13*1+6), so:

(x-3)+x+13*1+6

determiningTheFunctionDomain
(x-3)+x+6+13*1

We add all the numbers together, and all the variables

x+(x-3)+19

We get rid of parentheses

x+x-3+19

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)


We get rid of parentheses

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8