13=-(2y-4)+3y

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Solution for 13=-(2y-4)+3y equation: 



13=-(2y-4)+3y

We move all terms to the left:

13-(-(2y-4)+3y)=0



We calculate terms in parentheses: -(-(2y-4)+3y), so:

-(2y-4)+3y

We add all the numbers together, and all the variables

3y-(2y-4)

We get rid of parentheses

3y-2y+4

We add all the numbers together, and all the variables

y+4

Back to the equation:

-(y+4)



We get rid of parentheses

-y-4+13=0

We add all the numbers together, and all the variables

-1y+9=0

We move all terms containing y to the left, all other terms to the right

-y=-9

y=-9/-1

y=+9

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