13=-2(x-4)+3x

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Solution for 13=-2(x-4)+3x equation: 



13=-2(x-4)+3x

We move all terms to the left:

13-(-2(x-4)+3x)=0



We calculate terms in parentheses: -(-2(x-4)+3x), so:

-2(x-4)+3x

We add all the numbers together, and all the variables

3x-2(x-4)

We multiply parentheses

3x-2x+8

We add all the numbers together, and all the variables

x+8

Back to the equation:

-(x+8)



We get rid of parentheses

-x-8+13=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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