13=-2(y-4)+2y

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Solution for 13=-2(y-4)+2y equation: 



13=-2(y-4)+2y

We move all terms to the left:

13-(-2(y-4)+2y)=0



We calculate terms in parentheses: -(-2(y-4)+2y), so:

-2(y-4)+2y

We add all the numbers together, and all the variables

2y-2(y-4)

We multiply parentheses

2y-2y+8

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)



We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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