13=-2(y-4)=3y

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Solution for 13=-2(y-4)=3y equation: 



13=-2(y-4)=3y

We move all terms to the left:

13-(-2(y-4))=0



We calculate terms in parentheses: -(-2(y-4)), so:

-2(y-4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We get rid of parentheses

2y-8+13=0

We add all the numbers together, and all the variables

2y+5=0

We move all terms containing y to the left, all other terms to the right

2y=-5

y=-5/2

y=-2+1/2

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