13=-2(y-4+3y)

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Solution for 13=-2(y-4+3y) equation: 



13=-2(y-4+3y)

We move all terms to the left:

13-(-2(y-4+3y))=0

We add all the numbers together, and all the variables

-(-2(4y-4))+13=0



We calculate terms in parentheses: -(-2(4y-4)), so:

-2(4y-4)

We multiply parentheses

-8y+8

Back to the equation:

-(-8y+8)



We get rid of parentheses

8y-8+13=0

We add all the numbers together, and all the variables

8y+5=0

We move all terms containing y to the left, all other terms to the right

8y=-5

y=-5/8

y=-5/8

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