13=-3(21-y)+2(y-2)

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Solution for 13=-3(21-y)+2(y-2) equation: 



13=-3(21-y)+2(y-2)

We move all terms to the left:

13-(-3(21-y)+2(y-2))=0

We add all the numbers together, and all the variables

-(-3(-1y+21)+2(y-2))+13=0



We calculate terms in parentheses: -(-3(-1y+21)+2(y-2)), so:

-3(-1y+21)+2(y-2)

We multiply parentheses

3y+2y-63-4

We add all the numbers together, and all the variables

5y-67

Back to the equation:

-(5y-67)



We get rid of parentheses

-5y+67+13=0

We add all the numbers together, and all the variables

-5y+80=0

We move all terms containing y to the left, all other terms to the right

-5y=-80

y=-80/-5

y=+16

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