13=1+4(1+r)

Solution for 13=1+4(1+r) equation:

13=1+4(1+r)

We move all terms to the left:

13-(1+4(1+r))=0

We add all the numbers together, and all the variables

-(1+4(r+1))+13=0


We calculate terms in parentheses: -(1+4(r+1)), so:

1+4(r+1)

determiningTheFunctionDomain
4(r+1)+1

We multiply parentheses

4r+4+1

We add all the numbers together, and all the variables

4r+5

Back to the equation:

-(4r+5)


We get rid of parentheses

-4r-5+13=0

We add all the numbers together, and all the variables

-4r+8=0

We move all terms containing r to the left, all other terms to the right

-4r=-8

r=-8/-4

r=+2