13=1/2((2x+4)+(10x-50))

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Solution for 13=1/2((2x+4)+(10x-50)) equation: 



13=1/2((2x+4)+(10x-50))

We move all terms to the left:

13-(1/2((2x+4)+(10x-50)))=0



Domain of the equation: 2((2x+4)+(10x-50)))!=0

x∈R



We multiply all the terms by the denominator


-(1+13*2((2x+4)+(10x-50)))=0



We calculate terms in parentheses: -(1+13*2((2x+4)+(10x-50))), so:

1+13*2((2x+4)+(10x-50))

determiningTheFunctionDomain
13*2((2x+4)+(10x-50))+1

Wy multiply elements

26x((+1

Back to the equation:

-(26x((+1)



We add all the numbers together, and all the variables

-(26x(1=0

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