13=1/2(2x+4+10x-50)

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Solution for 13=1/2(2x+4+10x-50) equation: 



13=1/2(2x+4+10x-50)

We move all terms to the left:

13-(1/2(2x+4+10x-50))=0



Domain of the equation: 2(2x+4+10x-50))!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(12x-46))+13=0

We multiply all the terms by the denominator


-(1+13*2(12x-46))=0



We calculate terms in parentheses: -(1+13*2(12x-46)), so:

1+13*2(12x-46)

determiningTheFunctionDomain
13*2(12x-46)+1

Wy multiply elements

26x(1+1

Back to the equation:

-(26x(1+1)



We add all the numbers together, and all the variables

-(26x2=0

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