13=2(c-5)+15

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Solution for 13=2(c-5)+15 equation: 



13=2(c-5)+15

We move all terms to the left:

13-(2(c-5)+15)=0



We calculate terms in parentheses: -(2(c-5)+15), so:

2(c-5)+15

We multiply parentheses

2c-10+15

We add all the numbers together, and all the variables

2c+5

Back to the equation:

-(2c+5)



We get rid of parentheses

-2c-5+13=0

We add all the numbers together, and all the variables

-2c+8=0

We move all terms containing c to the left, all other terms to the right

-2c=-8

c=-8/-2

c=+4

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