13=2(y-4)+3y

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Solution for 13=2(y-4)+3y equation: 



13=2(y-4)+3y

We move all terms to the left:

13-(2(y-4)+3y)=0



We calculate terms in parentheses: -(2(y-4)+3y), so:

2(y-4)+3y

We add all the numbers together, and all the variables

3y+2(y-4)

We multiply parentheses

3y+2y-8

We add all the numbers together, and all the variables

5y-8

Back to the equation:

-(5y-8)



We get rid of parentheses

-5y+8+13=0

We add all the numbers together, and all the variables

-5y+21=0

We move all terms containing y to the left, all other terms to the right

-5y=-21

y=-21/-5

y=4+1/5

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