13=3(d+5)-4d

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Solution for 13=3(d+5)-4d equation:



13=3(d+5)-4d
We move all terms to the left:
13-(3(d+5)-4d)=0
We calculate terms in parentheses: -(3(d+5)-4d), so:
3(d+5)-4d
We add all the numbers together, and all the variables
-4d+3(d+5)
We multiply parentheses
-4d+3d+15
We add all the numbers together, and all the variables
-1d+15
Back to the equation:
-(-1d+15)
We get rid of parentheses
1d-15+13=0
We add all the numbers together, and all the variables
d-2=0
We move all terms containing d to the left, all other terms to the right
d=2

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