13=3(d+5)-4d

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Solution for 13=3(d+5)-4d equation: 



13=3(d+5)-4d

We move all terms to the left:

13-(3(d+5)-4d)=0



We calculate terms in parentheses: -(3(d+5)-4d), so:

3(d+5)-4d

We add all the numbers together, and all the variables

-4d+3(d+5)

We multiply parentheses

-4d+3d+15

We add all the numbers together, and all the variables

-1d+15

Back to the equation:

-(-1d+15)



We get rid of parentheses

1d-15+13=0

We add all the numbers together, and all the variables

d-2=0

We move all terms containing d to the left, all other terms to the right

d=2

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