13=3(x+1)+4(2x-3)

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Solution for 13=3(x+1)+4(2x-3) equation:



13=3(x+1)+4(2x-3)
We move all terms to the left:
13-(3(x+1)+4(2x-3))=0
We calculate terms in parentheses: -(3(x+1)+4(2x-3)), so:
3(x+1)+4(2x-3)
We multiply parentheses
3x+8x+3-12
We add all the numbers together, and all the variables
11x-9
Back to the equation:
-(11x-9)
We get rid of parentheses
-11x+9+13=0
We add all the numbers together, and all the variables
-11x+22=0
We move all terms containing x to the left, all other terms to the right
-11x=-22
x=-22/-11
x=+2

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