13=312/k

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Solution for 13=312/k equation: 



13=312/k

We move all terms to the left:

13-(312/k)=0



Domain of the equation: k)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

-(+312/k)+13=0

We get rid of parentheses

-312/k+13=0

We multiply all the terms by the denominator


13*k-312=0

We add all the numbers together, and all the variables

13k-312=0

We move all terms containing k to the left, all other terms to the right

13k=312

k=312/13

k=24

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