13=4+3(t+2)

Solution for 13=4+3(t+2) equation:

13=4+3(t+2)

We move all terms to the left:

13-(4+3(t+2))=0


We calculate terms in parentheses: -(4+3(t+2)), so:

4+3(t+2)

determiningTheFunctionDomain
3(t+2)+4

We multiply parentheses

3t+6+4

We add all the numbers together, and all the variables

3t+10

Back to the equation:

-(3t+10)


We get rid of parentheses

-3t-10+13=0

We add all the numbers together, and all the variables

-3t+3=0

We move all terms containing t to the left, all other terms to the right

-3t=-3

t=-3/-3

t=1