13=6(x-4)+(5+3)x

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Solution for 13=6(x-4)+(5+3)x equation: 



13=6(x-4)+(5+3)x

We move all terms to the left:

13-(6(x-4)+(5+3)x)=0

We add all the numbers together, and all the variables

-(6(x-4)+8x)+13=0



We calculate terms in parentheses: -(6(x-4)+8x), so:

6(x-4)+8x

We add all the numbers together, and all the variables

8x+6(x-4)

We multiply parentheses

8x+6x-24

We add all the numbers together, and all the variables

14x-24

Back to the equation:

-(14x-24)



We get rid of parentheses

-14x+24+13=0

We add all the numbers together, and all the variables

-14x+37=0

We move all terms containing x to the left, all other terms to the right

-14x=-37

x=-37/-14

x=2+9/14

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