13=7(4-2u)-6u

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Solution for 13=7(4-2u)-6u equation: 



13=7(4-2u)-6u

We move all terms to the left:

13-(7(4-2u)-6u)=0

We add all the numbers together, and all the variables

-(7(-2u+4)-6u)+13=0



We calculate terms in parentheses: -(7(-2u+4)-6u), so:

7(-2u+4)-6u

We add all the numbers together, and all the variables

-6u+7(-2u+4)

We multiply parentheses

-6u-14u+28

We add all the numbers together, and all the variables

-20u+28

Back to the equation:

-(-20u+28)



We get rid of parentheses

20u-28+13=0

We add all the numbers together, and all the variables

20u-15=0

We move all terms containing u to the left, all other terms to the right

20u=15

u=15/20

u=3/4

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