13=7-3(3b-2)

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Solution for 13=7-3(3b-2) equation: 



13=7-3(3b-2)

We move all terms to the left:

13-(7-3(3b-2))=0



We calculate terms in parentheses: -(7-3(3b-2)), so:

7-3(3b-2)

determiningTheFunctionDomain
-3(3b-2)+7

We multiply parentheses

-9b+6+7

We add all the numbers together, and all the variables

-9b+13

Back to the equation:

-(-9b+13)



We get rid of parentheses

9b-13+13=0

We add all the numbers together, and all the variables

9b=0

b=0/9

b=0

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