13j-1=(4j-7)/6

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Solution for 13j-1=(4j-7)/6 equation: 



13j-1=(4j-7)/6

We move all terms to the left:

13j-1-((4j-7)/6)=0

We multiply all the terms by the denominator


13j*6)-((4j-7)-1*6)=0

We add all the numbers together, and all the variables

13j*6)-((4j-7)=0

Wy multiply elements

78j^2=0

a = 78; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·78·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$j=\frac{-b}{2a}=\frac{0}{156}=0$

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