13m2-m-19=0

Solution for 13m2-m-19=0 equation:

13m^2-m-19=0

We add all the numbers together, and all the variables

13m^2-1m-19=0

a = 13; b = -1; c = -19;
Δ = b2-4ac
Δ = -12-4·13·(-19)
Δ = 989
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{989}}{2*13}=\frac{1-\sqrt{989}}{26}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{989}}{2*13}=\frac{1+\sqrt{989}}{26}
$