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13p^2-11p+1=0
a = 13; b = -11; c = +1;
Δ = b2-4ac
Δ = -112-4·13·1
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{69}}{2*13}=\frac{11-\sqrt{69}}{26} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{69}}{2*13}=\frac{11+\sqrt{69}}{26} $
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