13r-2(r+2)=5(4r-6)-10

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Solution for 13r-2(r+2)=5(4r-6)-10 equation: 



13r-2(r+2)=5(4r-6)-10

We move all terms to the left:

13r-2(r+2)-(5(4r-6)-10)=0

We multiply parentheses

13r-2r-(5(4r-6)-10)-4=0



We calculate terms in parentheses: -(5(4r-6)-10), so:

5(4r-6)-10

We multiply parentheses

20r-30-10

We add all the numbers together, and all the variables

20r-40

Back to the equation:

-(20r-40)



We add all the numbers together, and all the variables

11r-(20r-40)-4=0

We get rid of parentheses

11r-20r+40-4=0

We add all the numbers together, and all the variables

-9r+36=0

We move all terms containing r to the left, all other terms to the right

-9r=-36

r=-36/-9

r=+4

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