13r-4(r+4)=4(4r-4)-21

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Solution for 13r-4(r+4)=4(4r-4)-21 equation: 



13r-4(r+4)=4(4r-4)-21

We move all terms to the left:

13r-4(r+4)-(4(4r-4)-21)=0

We multiply parentheses

13r-4r-(4(4r-4)-21)-16=0



We calculate terms in parentheses: -(4(4r-4)-21), so:

4(4r-4)-21

We multiply parentheses

16r-16-21

We add all the numbers together, and all the variables

16r-37

Back to the equation:

-(16r-37)



We add all the numbers together, and all the variables

9r-(16r-37)-16=0

We get rid of parentheses

9r-16r+37-16=0

We add all the numbers together, and all the variables

-7r+21=0

We move all terms containing r to the left, all other terms to the right

-7r=-21

r=-21/-7

r=+3

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