13r-4(r+5)=5(3r-4)-18

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Solution for 13r-4(r+5)=5(3r-4)-18 equation: 



13r-4(r+5)=5(3r-4)-18

We move all terms to the left:

13r-4(r+5)-(5(3r-4)-18)=0

We multiply parentheses

13r-4r-(5(3r-4)-18)-20=0



We calculate terms in parentheses: -(5(3r-4)-18), so:

5(3r-4)-18

We multiply parentheses

15r-20-18

We add all the numbers together, and all the variables

15r-38

Back to the equation:

-(15r-38)



We add all the numbers together, and all the variables

9r-(15r-38)-20=0

We get rid of parentheses

9r-15r+38-20=0

We add all the numbers together, and all the variables

-6r+18=0

We move all terms containing r to the left, all other terms to the right

-6r=-18

r=-18/-6

r=+3

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