13t=16(t-1/3)

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Solution for 13t=16(t-1/3) equation:



13t=16(t-1/3)
We move all terms to the left:
13t-(16(t-1/3))=0
We add all the numbers together, and all the variables
13t-(16(+t-1/3))=0
We multiply all the terms by the denominator
13t*3))-(16(+t-1=0
We add all the numbers together, and all the variables
t+13t*3))-(16(-1=0
Wy multiply elements
39t^2+t-1=0
a = 39; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·39·(-1)
Δ = 157
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{157}}{2*39}=\frac{-1-\sqrt{157}}{78} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{157}}{2*39}=\frac{-1+\sqrt{157}}{78} $

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