13v+11=2(5+7v)-4

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Solution for 13v+11=2(5+7v)-4 equation: 



13v+11=2(5+7v)-4

We move all terms to the left:

13v+11-(2(5+7v)-4)=0

We add all the numbers together, and all the variables

13v-(2(7v+5)-4)+11=0



We calculate terms in parentheses: -(2(7v+5)-4), so:

2(7v+5)-4

We multiply parentheses

14v+10-4

We add all the numbers together, and all the variables

14v+6

Back to the equation:

-(14v+6)



We get rid of parentheses

13v-14v-6+11=0

We add all the numbers together, and all the variables

-1v+5=0

We move all terms containing v to the left, all other terms to the right

-v=-5

v=-5/-1

v=+5

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