13x*(4x+3)=0

Solution for 13x*(4x+3)=0 equation:

13x(4x+3)=0

We multiply parentheses

52x^2+39x=0

a = 52; b = 39; c = 0;
Δ = b2-4ac
Δ = 392-4·52·0
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-39}{2*52}=\frac{-78}{104}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+39}{2*52}=\frac{0}{104}
=0
$