13x+(-(-2x+12))=x+28

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Solution for 13x+(-(-2x+12))=x+28 equation: 



13x+(-(-2x+12))=x+28

We move all terms to the left:

13x+(-(-2x+12))-(x+28)=0

We get rid of parentheses

13x+(-(-2x+12))-x-28=0



We calculate terms in parentheses: +(-(-2x+12)), so:

-(-2x+12)

We get rid of parentheses

2x-12

Back to the equation:

+(2x-12)



We add all the numbers together, and all the variables

12x+(2x-12)-28=0

We get rid of parentheses

12x+2x-12-28=0

We add all the numbers together, and all the variables

14x-40=0

We move all terms containing x to the left, all other terms to the right

14x=40

x=40/14

x=2+6/7

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