13x+(12x-2)5=4(3x+2)+9x

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Solution for 13x+(12x-2)5=4(3x+2)+9x equation: 



13x+(12x-2)5=4(3x+2)+9x

We move all terms to the left:

13x+(12x-2)5-(4(3x+2)+9x)=0

We multiply parentheses

13x+60x-(4(3x+2)+9x)-10=0



We calculate terms in parentheses: -(4(3x+2)+9x), so:

4(3x+2)+9x

We add all the numbers together, and all the variables

9x+4(3x+2)

We multiply parentheses

9x+12x+8

We add all the numbers together, and all the variables

21x+8

Back to the equation:

-(21x+8)



We add all the numbers together, and all the variables

73x-(21x+8)-10=0

We get rid of parentheses

73x-21x-8-10=0

We add all the numbers together, and all the variables

52x-18=0

We move all terms containing x to the left, all other terms to the right

52x=18

x=18/52

x=9/26

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